Results 1 to 2 of 2

Math Help - help with the taylor series for a bonus problem

  1. #1
    thatguyinthesuit
    Guest

    help with the taylor series for a bonus problem

    hey all,

    i am stuck on a math problem that no one i've talked to can figure out. the idea is i have to find a taylor series in x - a through the term (x - a)^3 for the problem:

    2 - x + 3(x^2) - x^3 , a = -1

    if anyone has ANY idea at all how this is done, please let me know. thank you.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by thatguyinthesuit View Post
    hey all,

    i am stuck on a math problem that no one i've talked to can figure out. the idea is i have to find a taylor series in x - a through the term (x - a)^3 for the problem:

    2 - x + 3(x^2) - x^3 , a = -1

    if anyone has ANY idea at all how this is done, please let me know. thank you.
    put u=x-a, then x=u+a now substutute this into your expression to get:

    <br />
2 + (u+a) + 3(u+a)^2 -(u+a)^3<br />

    now expand the powers and collect terms to give a cubic in u and finaly replace u by x-a

    RonL
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Taylor series problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: May 10th 2011, 04:38 AM
  2. Taylor series problem
    Posted in the Differential Geometry Forum
    Replies: 3
    Last Post: February 23rd 2011, 04:43 PM
  3. taylor series problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: April 28th 2010, 06:39 PM
  4. taylor series problem
    Posted in the Calculus Forum
    Replies: 7
    Last Post: March 27th 2010, 08:17 AM
  5. Taylor series problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: May 27th 2009, 11:20 AM

Search Tags


/mathhelpforum @mathhelpforum