Can someone please help me solve this problem:
Let g(x)=x^3 f(x). Compute g'(2) given that f(2) = 3 and f'(2) = -1.
Any help with this problem would be much appreciated...
But as they said, you don't need to explicitly find f(x).
The derivative of g(x) is $\displaystyle g'(x) = 3x^2f(x) + x^3f'(x)$
You need to find $\displaystyle g'(2) = 3 \cdot 2^2 \cdot f(2) + 2^3 \cdot f'(2)$. You have f(2) and f'(2) - what more do you need?