Ok, I have differentiated g(x) = x^3 f(x) , which is g'(x) = 3x^2 f(x) + x^3 f'(x). Given that f(2) = 3 and f'(2) = -1, how do I find out what f(x) is? I'm stuck....
Ok, I have differentiated g(x) = x^3 f(x) , which is g'(x) = 3x^2 f(x) + x^3 f'(x). Given that f(2) = 3 and f'(2) = -1, how do I find out what f(x) is? I'm stuck....
But the question just asks you to compute g'(2). Why do you need f(x)?
Originally Posted by RU2010
Can someone please help me solve this problem:
Let g(x)=x^3 f(x). Compute g'(2) given that f(2) = 3 and f'(2) = -1.
Any help with this problem would be much appreciated...
f(x) is part of g(x), so I think I need to know what f(x) is in order to full differentiate g'(x). Since the problem gives the value of f(2)=3, and f'(2), I'm trying to use that information to find f(x). I'm still stuck.
But as they said, you don't need to explicitly find f(x).
The derivative of g(x) is
You need to find . You have f(2) and f'(2) - what more do you need?
But as they said, you don't need to explicitly find f(x).
The derivative of g(x) is
You need to find . You have f(2) and f'(2) - what more do you need?
Ok, the light bulb just came on! I see the answer now, and it was staring at me the entire time!