Use the Comparison Theorem to determine whether the integral is convergent/divergent: $\displaystyle \int_{0}^{1} \frac{sec^{2}x}{x\sqrt{x}} dx$
I dont know which basic function to compare it to. I tried comparing it to 1/x but that didnt work out.
Use the Comparison Theorem to determine whether the integral is convergent/divergent: $\displaystyle \int_{0}^{1} \frac{sec^{2}x}{x\sqrt{x}} dx$
I dont know which basic function to compare it to. I tried comparing it to 1/x but that didnt work out.