Results 1 to 3 of 3

Math Help - Improper integral (convergent/divergent)

  1. #1
    Member
    Joined
    Apr 2010
    Posts
    156

    Improper integral (convergent/divergent)

    Determine whether \int_{-\infty}^{\infty} xe^{-x^2}dx is convergent or divergent. Evaluate it if it is convergent. I tried using integration by parts, but failed to integrate e^{-x^2}.
    Last edited by SyNtHeSiS; August 26th 2010 at 02:56 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Aug 2009
    From
    Israel
    Posts
    976
    You don't need integration by parts.
    The substitution u=x^2 will easily solve this.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Ted
    Ted is offline
    Member
    Joined
    Feb 2010
    From
    China
    Posts
    199
    Thanks
    1
    Its = 0
    unless the lower limit is -infinity.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 8
    Last Post: November 26th 2010, 06:57 PM
  2. Improper integral convergent or divergent?
    Posted in the Calculus Forum
    Replies: 1
    Last Post: July 5th 2010, 12:47 PM
  3. Improper integral. Convergent or divergent?
    Posted in the Calculus Forum
    Replies: 2
    Last Post: May 2nd 2010, 06:20 AM
  4. Replies: 5
    Last Post: January 26th 2010, 04:56 AM
  5. convergent and divergent improper integrals
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 8th 2009, 09:15 AM

Search Tags


/mathhelpforum @mathhelpforum