Answer at the back of the book is different than what I come out. Im pretty sure there are different ways to get it, but If you would differentiate...
F(x)=3x^2 (5-x)^4
how would you get it to be f '(x)=(21x^2 - 14x)(x^3 -2x +1)^6 ?
tyvm!
Answer at the back of the book is different than what I come out. Im pretty sure there are different ways to get it, but If you would differentiate...
F(x)=3x^2 (5-x)^4
how would you get it to be f '(x)=(21x^2 - 14x)(x^3 -2x +1)^6 ?
tyvm!
That solution is not possible. I went ahead and did some of the work (before noticing that the solution is not possible) so I'll post it anyways. However, the original function was a 6th degree polynomial (if you have multiplied it all out), but the solution you posted is a 20th degree polynomial. That's clearly wrong.
Now, we can factor
exc...