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Thread: first quadrant.....

  1. May 28th 2007, 05:52 AM #1
    m777
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    first quadrant.....

    HELLO,
    PLEASE TRY TO SOLVE THIS QUESTION.
    Thanks
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  2. May 28th 2007, 07:38 AM #2
    ThePerfectHacker
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    \iint_D (x^2+y^2) \delta(x,y) dA = \iint_D (x^2+y^2) dA

    Convert to polar coordinates,

    \int_0^{\pi/2} \int_0^1 r^2 rdr d\theta
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  3. May 28th 2007, 07:58 AM #3
    CaptainBlack
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    Quote Originally Posted by m777 View Post
    HELLO,
    PLEASE TRY TO SOLVE THIS QUESTION.
    Thanks
    I think you will find the solution to this in this PDF document.

    RonL
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« Taylor Polynomials | Evaluate the integral »

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