# first quadrant.....

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• May 28th 2007, 05:52 AM
m777
first quadrant.....
HELLO,
PLEASE TRY TO SOLVE THIS QUESTION.
Thanks
• May 28th 2007, 07:38 AM
ThePerfectHacker
$\iint_D (x^2+y^2) \delta(x,y) dA = \iint_D (x^2+y^2) dA$

Convert to polar coordinates,

$\int_0^{\pi/2} \int_0^1 r^2 rdr d\theta$
• May 28th 2007, 07:58 AM
CaptainBlack
Quote:

Originally Posted by m777
HELLO,
PLEASE TRY TO SOLVE THIS QUESTION.
Thanks

I think you will find the solution to this in this PDF document.

RonL