Write . Can you graph ?
I have to find some level curves for:
So, if we call at the surface given by the equation , then
Now, that particular case its simple, cause it gives just a point, but if I go downwards I get:
I'm not sure how to represent this. How does this look on the xy plane?
I know that:
And
But it don't helps me to visualize the "curve". I know actually that it looks like a parallelogram, but thats because I've used mathematica to compute the surface :P I don't know how to deduce it analytically.
A level curve for f(x)= 1- |x|- |y| is given by 1- |x|- |y|= C, where C is a constant, or |x|+ |y|= 1- C.
Now, it should be obvious that, since the left side of that is never negative, C cannot be larger than 1.
If C= 1, the equation becomes |x|+ |y|= 0 which, since neither |x| nor |y| can be negative, is only true when x= y= 0. The level curve is the single point (0, 0).
For C< 1, as always with absolute values, the simplest thing to do is to break the problem into cases.
1. If x and y are both positive, |x|+ |y|= x+ y= 1- C. That is a straight line but remember to only draw it in the first quadrant.
2. If x< 0 and y> 0 then |x|+ |y|= -x+ y= 1- C. Again, a portion of a straight line but now in the second quadrant.
3. If x< 0 and y< 0 then |x|+ |y|= -x- y= 1- C. A portion of a straight line in the third quadrant.
4. If x> 0 and y< 0 then |x|+ |y|= x- y= 1- C. A portion of a straight line in the fourth quadrant.
If you draw those four segments for one value of C, say C= 0, it should be easy to see what the other level curves are.