Hi all,

The exact question is does the Kuhn Tucker method fail in this case:

max $\displaystyle x^3-y^2$ s.t. $\displaystyle x^2+y^2>1, x>0, y>0 $

I got that it does because in order to have the strict inequalities, we have to have the associated Lagrange multipliers = 0, but then we get x=y=0, which is obviously an inadmissible and incorrect answer.