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Math Help - Newton's Method

  1. #1
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    Exclamation Newton's Method

    Hi

    1.a) I know if the 1st approx is taken at x2, the tangent will be parallel to the x axis. But what about x1. Why cant i use it?

    2. b) Do I just say f"(0.6) and f"(0.8) are both negative and thus there must a stationary point in between?

    c) How exactly do you use Newton's method to find a stationary point?

    3. a) Could someone please give me hints to do this?

    Thank you!!!
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Sunyata View Post
    Hi

    1.a) I know if the 1st approx is taken at x2, the tangent will be parallel to the x axis. But what about x1. Why cant i use it
    Because it will converge to the other root.

    CB
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  3. #3
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    Quote Originally Posted by Sunyata View Post
    2. b) Do I just say f"(0.6) and f"(0.8) are both negative and thus there must a stationary point in between?
    No, it is because f'(x) has different signs at 0.6 and 0.8.

    CB
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  4. #4
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    Quote Originally Posted by Sunyata View Post
    c) How exactly do you use Newton's method to find a stationary point?
    You differentiate and then use Newtons method to find a root of f'(x)=0

    CB
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  5. #5
    Grand Panjandrum
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    Quote Originally Posted by Sunyata View Post
    3. a) Could someone please give me hints to do this?
    See here

    CB
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