1. ## Newton's Method

Hi

1.a) I know if the 1st approx is taken at x2, the tangent will be parallel to the x axis. But what about x1. Why cant i use it?

2. b) Do I just say f"(0.6) and f"(0.8) are both negative and thus there must a stationary point in between?

c) How exactly do you use Newton's method to find a stationary point?

3. a) Could someone please give me hints to do this?

Thank you!!!

2. Originally Posted by Sunyata
Hi

1.a) I know if the 1st approx is taken at x2, the tangent will be parallel to the x axis. But what about x1. Why cant i use it
Because it will converge to the other root.

CB

3. Originally Posted by Sunyata
2. b) Do I just say f"(0.6) and f"(0.8) are both negative and thus there must a stationary point in between?
No, it is because f'(x) has different signs at 0.6 and 0.8.

CB

4. Originally Posted by Sunyata
c) How exactly do you use Newton's method to find a stationary point?
You differentiate and then use Newtons method to find a root of f'(x)=0

CB

5. Originally Posted by Sunyata
3. a) Could someone please give me hints to do this?
See here

CB