1.a) I know if the 1st approx is taken at x2, the tangent will be parallel to the x axis. But what about x1. Why cant i use it?
2. b) Do I just say f"(0.6) and f"(0.8) are both negative and thus there must a stationary point in between?
c) How exactly do you use Newton's method to find a stationary point?
3. a) Could someone please give me hints to do this?