lim x-> 0 of sin5x/sinx

Is the answer 5?

Basically since its 0/0 i used L'hospitals rule and took the derivative of top and bottom to get:

5cos5x/cosx

which it then 5(1)/1... so =5?

But then i put it into this website that calculates it for you and it said the answer is 1 soo im a tad confused.