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Math Help - find slope of tangent line

  1. #1
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    find slope of tangent line

    A curve is given by the equation  y^3 + 220 = (e^x +1)^2
    find the slope of the tangent line at point (0, -6)
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by viet View Post
    A curve is given by the equation  y^3 + 220 = (e^x +1)^2
    find the slope of the tangent line at point (0, -6)
    \frac{d}{dx} [y^3 + 220] = \frac{d}{dx}(e^x +1)^2

    so:

    <br />
3y^2 \frac{dy}{dx} = 2(e^x+1)e^x<br />

    so at the required point:

    <br />
108 \frac{dy}{dx} = 4<br />

    RonL
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