1. ## Derivative ae^(b theta)

Good afternoon,

What is the method fo differentiating the following:

$
\displaystyle ae^{b\theta}
$

Is it as simple as...

$
\displaystyle abe^{b\theta}
$

I was looking for an explanation of the rules involved with this particular situation, but could not find what I was looking for.

2. Forgot...

The a and b are positive constants. So, I would assume that would make my guess as to the answer correct.

3. Originally Posted by MechEng
Good afternoon,

What is the method fo differentiating the following:

$
\displaystyle ae^{b\theta}
$

Is it as simple as...

$
\displaystyle abe^{b\theta}
$

I was looking for an explanation of the rules involved with this particular situation, but could not find what I was looking for.
The chain rule

$f(x)=ae^{x}$ and $x=b\theta$

The chain rule gives

$\displaystyle \frac{df}{d\theta}=\frac{df}{dx}\frac{dx}{d\theta} =ae^{x}b=abe^{b\theta}$

4. That's what I was thinking... I've been second guessing myself too much.

Thank you!