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Math Help - Improper Integral

  1. #1
    Newbie
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    Aug 2010
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    Improper Integral

    My question read

    integrate (0 to infinity) 1/((x+1)(x^2+1))..so i
    wrote

    limit as A approaches infinity int (0 to A) (1/((x+1)(x^2+1))

    I tried integrating by using variables A and B so that they have a common denominator...I ve made no progress for a while now plz help
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  2. #2
    MHF Contributor Amer's Avatar
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    May 2009
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    Jordan
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    \frac{1}{(x+1)(x^2+1)} = \frac{A}{(x+1)} + \frac{Bx+C}{x^2+1}

    find A,B,C

    \frac{1}{(x+1)(x^2+1)} = \frac{1/2}{x+1} + \frac{-1/2x+1/2}{x^2+1}
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