How do I integrate this integral using partial fractions?
\int_ dx/( Asin[x] + Bcos[x])^2 where a =/ 0
Thanks
Hello, Befordxide!
I have a back-door approach . . .
In the denominator we have: .
Multiply top and bottom by : .
Let be an acute angle in a right triangle with: .
. . Then: . . . . Note that: .
. . Hence: .
Then we have: .
The denominator becomes: .
The integral becomes: .
Can you finish it now?