How do I integrate this integral using partial fractions?

\int_ dx/( Asin[x] + Bcos[x])^2 where a =/ 0

Thanks

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- May 23rd 2007, 08:03 PMBefordxideintegration by partial fractions
How do I integrate this integral using partial fractions?

\int_ dx/( Asin[x] + Bcos[x])^2 where a =/ 0

Thanks - May 24th 2007, 07:37 PMThePerfectHacker
- May 25th 2007, 11:08 AMSoroban
Hello, Befordxide!

I have a back-door approach . . .

Quote:

In the denominator we have: .

Multiply top and bottom by : .

Let be an acute angle in a right triangle with: .

. . Then: . . . . Note that: .

. . Hence: .

Then we have: .

The denominator becomes: .

The integral becomes: .

Can you finish it now?