Ley $y=g(h(x))$ where $h(x)=x^2/(x+2)$. if $g'(9/5)=-2$,find $dy/dx$ where x=3.
Ley $y=g(h(x))$ where $h(x)=x^2/(x+2)$. if $g'(9/5)=-2$,find $dy/dx$ where x=3.