Ley $\displaystyle y=g(h(x))$ where $\displaystyle h(x)=x^2/(x+2)$. if $\displaystyle g'(9/5)=-2$,find $\displaystyle dy/dx$ where x=3.

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- Aug 9th 2010, 11:35 AMilovemymathDerivative of function
Ley $\displaystyle y=g(h(x))$ where $\displaystyle h(x)=x^2/(x+2)$. if $\displaystyle g'(9/5)=-2$,find $\displaystyle dy/dx$ where x=3.

- Aug 9th 2010, 12:06 PMGeneral
You have asked the same question here:

http://www.mathhelpforum.com/math-he...es-153112.html - Aug 9th 2010, 12:34 PMArchie Meade