Ley $\displaystyle y=g(h(x))$ where $\displaystyle h(x)=x^2/(x+2)$. if $\displaystyle g'(9/5)=-2$,find $\displaystyle dy/dx$ where x=3
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$\displaystyle \dfrac{dy}{dx}=g'(h(x)) \cdot h'(x)$
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