Find the inflection points for the function: f(x) = 8x + 3 - 2sinx on the interval from 0 to 3pi. Give x values only and round to three decimal places.
Another example of a problem that I understand in general, but the specific problem throws me off...I differentiated twice and got f''(x) = 2sinx
I set that to zero and got sinx = -2
I assume this means there is an inflection point at -2, correct? This should be simple but trig functions always throw me off.
No. If you're saying thatOriginally Posted by bobsanchez
, you set equal to 0:
... DIVIDE both sides by 2:
You're looking for angles whose sine is 0. You should have learned in trig that that occurs when. (You say that the interval is from 0 to 3pi, but I don't know if you mean
or
.)
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