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Math Help - Spring

  1. #1
    MHF Contributor alexmahone's Avatar
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    Spring

    A spring has a natural length of 2 ft, and a force of a 15 lb is required to hold it compressed at a length of 18 in. How much work is done in stretching this spring from its natural length to a length of 3 ft?

    Working:

    18 in=\frac{18}{12} ft=1.5 ft

    x=compression=2-1.5=0.5 ft

    F=kx

    15=k*0.5

    k=30 lb/ft

    W=\frac{1}{2}kx_2^2-\frac{1}{2}kx_1^2

    = \frac{1}{2}k(x_2^2-x_1^2)

    = \frac{30}{2}(1^2-0^2)

    = 15*1

    = 15 lb-ft

    Edit: Never mind; I solved it myself.
    Last edited by alexmahone; August 7th 2010 at 09:05 PM. Reason: Solved
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