Ok

Q1) Solve (x^3) - 7x + 6 = 0

Q2) ∫▒〖sec4xtan4x dx〗

if the above isn't readable, i meant find: ∫sec6xtan6x dx

(Giggle) Thanks for any help xD (Lipssealed)

- August 6th 2010, 02:27 AMMathsWhizA series of problems... (don't be afraid it's only maths questions)
Ok

Q1) Solve (x^3) - 7x + 6 = 0

Q2) ∫▒〖sec4xtan4x dx〗

if the above isn't readable, i meant find: ∫sec6xtan6x dx

(Giggle) Thanks for any help xD (Lipssealed) - August 6th 2010, 02:40 AMProve It
.

It's pretty easy to see that , so is a factor.

Long dividing gives

.

So if

or or .

So or or . - August 6th 2010, 02:42 AMHallsofIvy
Have you tried

**anything**at all? For example, have you looked at what happens if x= 1?

Quote:

Q2) ∫▒〖sec4xtan4x dx〗

if the above isn't readable, i meant find: ∫sec6xtan6x dx

sec 6x= 1/cos(6x) and tan(6x)= sin(6x)/cos(6x) so this is sin(6x)/cos^2(6x). Let u= cos 6x.

Quote:

Q3) Solve: log(x) + log(x+1) = 1

Quote:

Q4) It is given cos(θ) = 5/13 and that sin(θ) is negative. Find the exact value of tan(θ/2).

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Q5) The graphs of y -4x^2 and y = 6 - 2x intersect at x =1. Find the size of the acute angle between these curves at x = 1 correct to the nearest minute.

Quote:

i) Express 3cosx - √3sinx in the form R cos (x +a)

Quote:

(Giggle) Thanks for any help xD (Lipssealed)

In future,**try**yourself and show what you have tried. - August 6th 2010, 02:43 AMProve It

So or . - August 6th 2010, 03:02 AMHallsofIvy
Captain Black, did you edit to remove problems? Why?

- August 6th 2010, 03:27 AMMathsWhiz
- August 6th 2010, 04:05 AMProve It
- August 6th 2010, 04:42 AMmr fantastic
Thread closed.

- August 6th 2010, 04:47 AMmr fantastic