Hi

I am having trouble getting the correct answer to the following question:

1) The sides of a right angle triangle enclosing the right angle are measured as 6.0m and 8.0m respectively. The maximum errors in each measurement are +- 0.1m

i) Find approximately the maximum error in the calculated area of the triangle.

This is what i have done:

$\displaystyle A=\frac{1}{2}bh$

$\displaystyle \partial A = \frac{\partial A}{\partial a} * \partial a + \frac{\partial A}{\partial b} * \partial b

$

$\displaystyle \frac{\partial A}{\partial a}$

$\displaystyle =\frac{1}{2}b$

sub b=8.0m

$\displaystyle =4$

$\displaystyle \frac{\partial A}{\partial b}$

$\displaystyle =\frac{1}{2}h$

sub h=6

$\displaystyle =3$

$\displaystyle \partial a = \frac{0.1}{4} $

$\displaystyle = 0.025$

$\displaystyle \partial b = \frac{0.1}{3}$

$\displaystyle = 0.033$

$\displaystyle \partial A = \frac{4}{0.025} * 0.025 \frac{3}{0.033} * 0.033$

$\displaystyle =7$

P.S