f(x) = ln[(1+x^2)/(1-x^2)] = ln(1+x^2) - ln(1-x^2) i know log(1+x) = x^n+1 / n+1 but i dont know how i am supposed to modify the equation or whatever to get what i need...
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Originally Posted by jeph f(x) = ln[(1+x^2)/(1-x^2)] = ln(1+x^2) - ln(1-x^2) i know log(1+x) = x^n+1 / n+1 but i dont know how i am supposed to modify the equation or whatever to get what i need... Now to find, use And, To find, use And combine them together.
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