Remember that .
So
.
I think you can see that this is a Quadratic, and since and for all , that means .
Eliminate t in the following equations to determine the type of curve represented.
x = cos t , y= 1 - cos 2t
I have so far managed to reduce the y=1-cos2t equation to 0 ? ,by using the addition formula and subing in x,to get rid of t.........but the ans is y= 2(1-x^2) ,-1<x<1.