can someone double check this? Thanks edit: for the second row and 3rd row, I meant to write X instead of r
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$\displaystyle \displaystyle \frac{x^2}{x+4} = x - 4 + \frac{16}{x+4}$
how did you get x-4? thanks
ooo i got it! thanks!
Code: x - 4 .............................. x+4 | x^2 x^2 + 4x .................. - 4x - 4x - 16 .............. 16
x - 4 .............................. x+4 | x^2 x^2 + 4x .................. - 4x - 4x - 16 .............. 16
Or $\displaystyle \frac{x^2}{x+ 4}= \frac{x^2- 16+ 16}{x+ 4}= \frac{x^2- 16}{x+ 4}+ \frac{16}{x+ 4}$$\displaystyle = \frac{(x- 4)(x+ 4)}{x- 4}+ \frac{16}{x+ 4}= x- 4+ \frac{16}{x+ 4}$.
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