trying ti do a problem
I need the intregal of [(3/2)-2cos(2x)+((1/2)cos(4x)]
i got (3/2)x -4sin(2x) + 2cos(4x)+c
is that right?
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When you do u substitution on the second term, for instance:
so for the rest of the problem, I take it from the bonds 0 to pi.
I got pi/4 [(3/2)pi-sin92pi)+(1/8)sin(4pi)]- (pi/4)[0-sin(0)-(1/8)sin(0)]
what is the final answer to this?
I'm not sure what you're doing, but if this is a definite integral going from 0 to pi, then you would have
yeah urs looks like what I have, except there is a pi/4 outside the integral. how do I put that in? I have to put multiply it to both ()'s before subtracting them right?
Grr, please state the ENTIRE problem next time. So I'm guessing that the problem was this:
After taking the integral you get:
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