Need to prove that the formula for the volume of water V in a hemispherical bowl of radius r when the depth of water is h is given by: V = ((pi*h^2)/3) * (3r-h) I assume using integration. Solids of revolution maybe? Any help appreciated. Thanks
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Originally Posted by anonymous_maths Need to prove that the formula for the volume of water V in a hemispherical bowl of radius r when the depth of water is h is given by: V = ((pi*h^2)/3) * (3r-h) I assume using integration. Solids of revolution maybe? Any help appreciated. Thanks Draw a diagram. Let be the variable depth and be the variable radius. = = = = =
Originally Posted by anonymous_maths Need to prove that the formula for the volume of water V in a hemispherical bowl of radius r when the depth of water is h is given by: V = ((pi*h^2)/3) * (3r-h) I assume using integration. Solids of revolution maybe? Any help appreciated. Thanks Draw a diagram, and the method of disks looks like the easiest method. CB
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