Originally Posted by

**Kristen** Here is the factoids from the original problem:

F(0) = 6

lim(x -> infinity) F(x) = 30

rate of population growth = $\displaystyle (A*e^t)/((.02*A+e^t)^2)$

where t is a continuous variable and t >= 0

I need to figure out at what t will the population reach 10.

I managed to figure out that A = 46.15, but after that I get lost.

The book says I should be solving for t with the equation $\displaystyle 30-((46.15)/(.923+e^t)) = 10$, but I keep coming up with the equation $\displaystyle 6+((46.15)/(.923+e^t)) = 10$ and I don't know where I am going wrong.

If anyone has some insight for me, that would be super. I've been trying to figure this out for two days now and I need some help.

Thanks.