i just would like someone to check my work on this one i think ive done it correctly
f(x)= x^3+x^2-x-17
f' = 3x^2-2x-1
3x^2-2x-1=0
(3x+1)(x-1)=0
x= 1, -1/3
1^3+1^2-1-17=-16
(-1/3)^3+(-1/3)^2-(-1/3)-17=-17.3
(1, -16), (-1/3,-17.3)
i just would like someone to check my work on this one i think ive done it correctly
f(x)= x^3+x^2-x-17
f' = 3x^2-2x-1
3x^2-2x-1=0
(3x+1)(x-1)=0
x= 1, -1/3
1^3+1^2-1-17=-16
(-1/3)^3+(-1/3)^2-(-1/3)-17=-17.3
(1, -16), (-1/3,-17.3)