$\displaystyle \int\frac{cos(x)}{1+sin(x)} dx$

i need a little help evaluating this problem

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- May 22nd 2007, 10:50 AMvietintegral help
$\displaystyle \int\frac{cos(x)}{1+sin(x)} dx$

i need a little help evaluating this problem - May 22nd 2007, 11:27 AMJhevon
- May 22nd 2007, 12:09 PMviet
i guess its a two stepper thanks

- May 30th 2007, 11:53 AMKrizalid
$\displaystyle \int {\frac{{\cos x}}

{{1 + \sin x}}\,dx} = \int {\frac{{(1 + \sin x)'}}

{{1 + \sin x}}\,dx} = \ln \left| {1 + \sin x} \right| + c$

It's useful remember that $\displaystyle \int {\frac{{f'(x)}}

{{f(x)}}\,dx} = \ln \left| {f(x)} \right| + c$