Here's the problem

limit (sqrt(x^2+5x)-x)

x->[infinity]

The answer is (according to two websites and my calculator) 5/2.

Here's the work I've done so far.

[Multiply the conjugate]

(sqrt(x^2+5x)-x)/1 * (sqrt(x^2+5x)+x)/(sqrt(x^2+5x)+x)

x^2+5x-x^2/(sqrt(x^2+5x)+x) = 5x/(sqrt(x^2+5x)+x)

and I don't know how to get farther than that. Please help!