Rate of Change Problem
Hi all, first time here. Not sure whether this is the right category...
I am working with water levels and a truncated cone.
I have been told that V = (pi/3)(((x+2)^3)/4)-2000).
I am then told to find dV/dx, which = (pi(x^2+40x+400)/4).
This is where I am stuck, because it then asks "Hence find the rate of change of height (x) in terms of x.
Would I use Chain Rule, or is it simply dV/dx inverse?
I'm not sure at all.
Thanks for the help.
Sorry, but I disagree with your derivative. If
Whoops, meant to write (x+20)^3, not (x+2)^3.
any information given about how the volume is changing w/r to time?
Originally Posted by Etherlite
Don't worry all, I realised on a previous page that they gave me the rate at which water is dripping into the bucket.
Originally Posted by skeeter
Apply chain rule, and the answer's there.