integral x^3[sqrt(9+x^2)] i know i am supposed to use trig sub but i am having a very confusing time trying to remember how its done.....
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Originally Posted by jeph integral x^3[sqrt(9+x^2)] i know i am supposed to use trig sub but i am having a very confusing time trying to remember how its done..... Let, then And, and Thus, and After this substitution we have, Can you do it frum heir?
Let's set , this yields Regards
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