integral x^3[sqrt(9+x^2)]

i know i am supposed to use trig sub but i am having a very confusing time trying to remember how its done.....

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- May 21st 2007, 05:57 PMjephintegrate
integral x^3[sqrt(9+x^2)]

i know i am supposed to use trig sub but i am having a very confusing time trying to remember how its done..... - May 21st 2007, 06:19 PMThePerfectHacker
- May 30th 2007, 12:14 PMKrizalid
Let's set , this yields

Regards :D