Question :

integral from 1 to 2 of (4+u^2)/u^3

My work:

integreal 4/u^3+ integral u^2/u^3

4integral 1/u^3 + integral (u^2)(1/u^3)

4 integral u^-3 + integral (u^2)(u^-3)

4 integral (u^-2)/-2 + integral (u^3/3)(u^-2/-2)

4 [[(2^-2)/-2] -[(1^-2)/-2]} +{ [(2^3/3)(2^-2/-2)]-[(1^3/3)(1^-2/-2)]}

Now im stuck because i want to make my answer clean in a fraction. i can solve it usiing decimals but how would i re write it soo i end up dealing with fractions?