integral abs sinx [0,3pi/2]

would this be -cosx(abs sinx/sinx)?

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- Jul 28th 2010, 07:08 PMkensingtonintegral abs sinx [0,3pi/2]
integral abs sinx [0,3pi/2]

would this be -cosx(abs sinx/sinx)? - Jul 28th 2010, 07:15 PMmr fantastic
- Jul 28th 2010, 10:02 PMautumn
You cannot ignore the absolute value.

Break up the integral into the parts where sin x is positive and negative and flip the negative part over.

Then you can integrate. - Jul 29th 2010, 05:05 AMkensington
what do you mean flip the negative part over?

- Jul 29th 2010, 05:16 AMVlasev
- Jul 29th 2010, 06:25 AMkensington
- Jul 29th 2010, 06:58 AMPlato
This may surprise you but: $\displaystyle \int_0^{\frac{{3\pi }}

{2}} {\left| {\sin (x)} \right|dx} = 3\int_0^{\frac{\pi }

{2}} {\sin (x)dx} $.

Think about it after looking at the graph. - Jul 29th 2010, 07:06 AMkensington
- Jul 29th 2010, 07:08 AMPlato
No. The answer is 3.

- Aug 1st 2010, 10:08 PMmatheagle