Hi,
I just want to make sure I am doing this right.
Find the average value of the function n the given interval
f(x)=sec^2 (x/2) [0, pi/2]
So I integrated from 0 to pi/2. but I am stuck on what the anti derivative of sec^2 (x/2) is... I know the anti derivative of sec^2 (x) is tan (x)...
Thanks
Can you help with this problem? I don't even know what it is asking.. It's the same type of problem
If f ave i[a,b] denotes the average value of f on the interval [a,b] and a<c<b, show that
f ave[a,b] = (c-a)/(b-a) f ave[a,b]+ (b-c)/(b-a) f ave[c,b]
ave means average.
Much thanks! I am stomped on that one.
I am not sure..... I wish I had a scanner. It basically says this:
If f ave[a,b] denotes the average value of f on the interval [a,b] and a<c<b, show that
f ave[a,b] = (c-a)/(b-a) f ave[a,b]+ (b-c)/(b-a) f ave[c,b]
ave means average.
So I am guessing i have to proof it?