Thread: [SOLVED] Integral

Evaluate the integral int_{-1,3} (t^3)(4 + t^3)^(-1/2) dt,
given that

int_{-1,3} (4 + t^3)^(1/2) dt = 11.35.

Leave the answer in terms of sqrt(3) and sqrt(31).

Thanks in advance

Originally Posted by Burtsemily

Evaluate the integral int_{-1,3} (t^3)(4 + t^3)^(-1/2) dt,
given that

int_{-1,3} (4 + t^3)^(1/2) dt = 11.35.

Leave the answer in terms of sqrt(3) and sqrt(31).

Thanks in advance

Write:

int_{-1,3} (t^3)(4 + t^3)^(-1/2) dt = int_{-1,3} [t] [(t^2)(4 + t^3)^(-1/2)] dt

then use integrtation by parts with u = t and dv = [(t^2)(4 + t^3)^(-1/2)]

RonL