Evaluate the integral int_{-1,3} (t^3)(4 + t^3)^(-1/2) dt, given that int_{-1,3} (4 + t^3)^(1/2) dt = 11.35. Leave the answer in terms of sqrt(3) and sqrt(31). Thanks in advance
Last edited by Burtsemily; May 21st 2007 at 12:02 AM. Reason: The integral looks a little messy, let me fix it up a little:
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Originally Posted by Burtsemily Evaluate the integral int_{-1,3} (t^3)(4 + t^3)^(-1/2) dt, given that int_{-1,3} (4 + t^3)^(1/2) dt = 11.35. Leave the answer in terms of sqrt(3) and sqrt(31). Thanks in advance Write: int_{-1,3} (t^3)(4 + t^3)^(-1/2) dt = int_{-1,3} [t] [(t^2)(4 + t^3)^(-1/2)] dt then use integrtation by parts with u = t and dv = [(t^2)(4 + t^3)^(-1/2)] RonL