Consider the the cardioid r=1+sin(θ)
find dy/dx. I'm a little unsure where to start here, I'm guessing convert it which, I got x^2 + y^2= (1+sin(θ))^2, am I going in the right direction? Any guidance would be appreciated. Thanks
Consider the the cardioid r=1+sin(θ)
find dy/dx. I'm a little unsure where to start here, I'm guessing convert it which, I got x^2 + y^2= (1+sin(θ))^2, am I going in the right direction? Any guidance would be appreciated. Thanks
OK so I did a little more work, and figure I should times both sides by r instead of squaring it.
which gave me:
r^2= r + rsin(t)
x^2+y^2=r+y
r= (x^2+y^2-y)
r^2= (x^2+y^2-y)^2
x^2+y^2= (x^2+y^2-y)^2
But I'm still stuck on how to find the derivative of this? [dy/dx] = [dy/dt / dx/dt ]