Finding the Surface Area of the curve?
y = 1/x
1 ≤ x ≤ ∞ about x-axis.
Thanks
Actually, I think you have an error in your integration. I checked it, and there's a problem:
$\displaystyle \int \frac{1}{x}\sqrt{1+\frac{1}{x^4}dx$
Add the fractions in the radical $\displaystyle \sqrt{\frac{x^4+1}{x^4}}=\frac{\sqrt{1+x^4}}{x^2}$
Plug this into the integral to get $\displaystyle \int \frac{\sqrt{1+x^4}}{x^3}dx$.