Find an equation of the tangent line to the curve at the given point. Leave your answer solved for y.
Y=(1+x)cosx (0,1)
Okay, so I think you just take the derivative of the function, but how do I do that and make the rest of the problem work?
Find an equation of the tangent line to the curve at the given point. Leave your answer solved for y.
Y=(1+x)cosx (0,1)
Okay, so I think you just take the derivative of the function, but how do I do that and make the rest of the problem work?
Why did you suspect to take the derivative ?
The derivative gives the slope of the tangent.
The tangent is a straight line.
The point (0,1) is x=0, y=1 corresponding to a point on the tangent, the point of tangency to the curve.
To make the rest of the problem work......
How do you write the equation of a straight line?
If you have 2 fixed points, you can do it.
If you have a fixed point and the slope you can do it.
What do you do here?