f(x) = squaroot(x) -(1/7)x

[0, 49]

- Jul 22nd 2010, 10:05 AMsuperduper1Find the number c that satisfies the conclusion of Rolle's Theorem.
f(x) = squaroot(x) -(1/7)x

[0, 49] - Jul 22nd 2010, 10:46 AMeumyang
$\displaystyle f(x) = \sqrt{x} - \frac{1}{7}x$

Find the derivative of f(x) and set equal to 0:

$\displaystyle \begin{aligned}

f(x) &= x^{1/2} - \frac{1}{7}x \\

f'(x) &= \frac{1}{2}x^{-1/2} - \frac{1}{7} \\

0 &= \frac{1}{2 \sqrt{x}} - \frac{1}{7} \\

\end{aligned}$

Can you finish? - Jul 22nd 2010, 05:28 PMsuperduper1
1/2(sqaroot(x)) = 1/7

move -1/7 to other side of equal side

cross multiply to solve for x

49/4

thank you

Also, how do I write out the equation like you did? For example, instead of using squarootx i can write out the actual square root symbol? - Jul 22nd 2010, 07:14 PMeumyang
Learn LaTeX. While you're in the editing window, at the end of the 2nd row of formatting/functions (the one that starts with bold, italics, underline), you'll see the TeX button. Click it, and the math tags appear:

[ MATH ][ /MATH ]

(I added extra spaces so that the tags would appear.) You'll have to learn the syntax to type the equations in. Look at the LaTeX Help subforum. Here's what I typed so that the original equation would appear:

[ MATH ]f(x) = \sqrt{x} - \frac{1}{7}x[ /MATH ]

$\displaystyle f(x) = \sqrt{x} - \frac{1}{7}x$

(again, without the extra spaces).