$\displaystyle y = e^{2x}(1 - x)$

$\displaystyle y = e^{2x} - xe^{2x}$

$\displaystyle y^{'} = 2e^{2x} - 2xe^{2x} + e^{2x}$

$\displaystyle y^{'} = 3e^{2x} - 2xe^{2x}$

It's part of a larger question, so there's no solution in my textbook that I can check with. Thank you.