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Math Help - Could someone verify this derivation for me?

  1. #1
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    Could someone verify this derivation for me?

    y = e^{2x}(1 - x)
    y = e^{2x} - xe^{2x}
    y^{'} = 2e^{2x} - 2xe^{2x} + e^{2x}
    y^{'} = 3e^{2x} - 2xe^{2x}

    It's part of a larger question, so there's no solution in my textbook that I can check with. Thank you.
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  2. #2
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    Quote Originally Posted by Glitch View Post
    y = e^{2x}(1 - x)
    y = e^{2x} - xe^{2x}
    y^{'} = 2e^{2x} - 2xe^{2x} + e^{2x}
    y^{'} = 3e^{2x} - 2xe^{2x}

    It's part of a larger question, so there's no solution in my textbook that I can check with. Thank you.
    That is correct, I'd write it as:

    y^{'} = e^{2x}(3 - 2x)
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  3. #3
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    Indeed, that is neater. Thanks!
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  4. #4
    A Plied Mathematician
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    Your derivative is incorrect here. You forgot that the minus sign also applies to the third term in the first line where you take the derivative. That is,

    y' = 2e^{2x} - 2xe^{2x} - e^{2x}.

    This will impact, possibly, your other post.
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