Hi all.

My battle with calculus is forever ongoing, although I feel I've made lots of progress recently. However I am a bit unsure on how to go about the following:

$\displaystyle \int \sqrt{9 + cos x}$

I am aware that:

$\displaystyle \int \sqrt{9 + cos x}= \int (9 + cos x)^\frac{1}{2}$

but am still stumped.

Any pointers would be greatly appreciated.

Mav