1. For the following function: y= x^3/3+ 2x^2 + 3x - 1 a. Find the stationary points. b. Use the second-order derivatives to test whether the stationary points are at a maximum or minimum value of. thank you for your help
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a. find f''(x), then x1 and x2 of f'(x)=0
b. find f''(x), if f''(xt)>0 then xt min. if f''(xt),0 xt max. if f''(xt)=0 and f'''(xt)!=0 then it is nor max/min.
thanks however i am clueless to finding f''(x), then x1 and x2 of f'(x)=0
when u put means that There u have stationary points...
lol... u can go from here ?
just put stationary points in so it's min because it's so it's max because it's
Last edited by yeKciM; July 20th 2010 at 08:35 AM.
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