Thread: stationary points?

1. For the following function:


y= x^3/3+ 2x^2 + 3x - 1



a. Find the stationary points.
b. Use the second-order derivatives to test whether the stationary points are at a
maximum or minimum value of.

thank you for your help

a. find f''(x), then x1 and x2 of f'(x)=0
b. find f''(x), if f''(xt)>0 then xt min. if f''(xt),0 xt max. if f''(xt)=0 and f'''(xt)!=0 then it is nor max/min.

thanks however i am clueless to finding f''(x), then x1 and x2 of f'(x)=0

when u put means that

There u have stationary points...



lol... u can go from here ?

just put stationary points in

so it's min because it's
so it's max because it's