1.For the following function:

y= x^3/3+ 2x^2 + 3x - 1

a.Find the stationary points.

b.Use the second-order derivatives to test whether the stationary points are at a

maximum or minimum value of.

thank you for your help

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- July 19th 2010, 03:23 PMarslanstationary points?
**1.****For the following function:**

**y= x^3/3+ 2x^2 + 3x - 1**

**a.****Find the stationary points.**

**b.****Use the second-order derivatives to test whether the stationary points are at a**

**maximum or minimum value of****.**

**thank you for your help**

- July 19th 2010, 03:46 PMAlso sprach Zarathustra
a. find f''(x), then x1 and x2 of f'(x)=0

b. find f''(x), if f''(xt)>0 then xt min. if f''(xt),0 xt max. if f''(xt)=0 and f'''(xt)!=0 then it is nor max/min. - July 20th 2010, 06:08 AMarslan
thanks however i am clueless to finding f''(x), then x1 and x2 of f'(x)=0

- July 20th 2010, 08:10 AMyeKciM

when u put means that

There u have stationary points...

lol... u can go from here ?

just put stationary points in

so it's min because it's

so it's max because it's