f a ball is thrown into the air with a velocity of 45 ft/s, its height in feet after t seconds is given by y = 45t - 13t^2. Find the instantaneous velocity when t=2.
f a ball is thrown into the air with a velocity of 45 ft/s, its height in feet after t seconds is given by y = 45t - 13t^2. Find the instantaneous velocity when t=2.
Would the answer to this be -7?
Is that what you get when you substitute t = 2 into dy/dt? If so, then it's correct.