Find the point of intersection, P, of the lines L1 = (x-6)/3 = (y - 6)/1 = (z - 2)/4 L2 = (x - 8)/1 = (y - 5)/2 = (z - 4)/2 Thanks
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oooops...
Last edited by Also sprach Zarathustra; July 19th 2010 at 12:22 PM.
Yeah I got that far, then it said something about multiplying equations 2 * 3 and then adding to equation 1 or something like that and that's where i got confused. I couldn't get it into p(x, y, z) form.
and... ooops...
Last edited by Also sprach Zarathustra; July 19th 2010 at 12:23 PM.
Write each in parametric form. Now solve for the parameters.
The equations were right just the algebra was wrong. I just recalculated them and got it correct. Thanks!
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