Find the point of intersection, P, of the lines ...

**foojy** · July 19th 2010, 10:37 AM

Find the point of intersection, P, of the lines

L1 = (x-6)/3 = (y - 6)/1 = (z - 2)/4
L2 = (x - 8)/1 = (y - 5)/2 = (z - 4)/2

Thanks

**Also sprach Zarathustra** · July 19th 2010, 10:47 AM

oooops...

**foojy** · July 19th 2010, 10:54 AM

Yeah I got that far, then it said something about multiplying equations 2 * 3 and then adding to equation 1 or something like that and that's where i got confused. I couldn't get it into p(x, y, z) form.

**Also sprach Zarathustra** · July 19th 2010, 11:53 AM

and... ooops...

**Plato** · July 19th 2010, 12:19 PM

Write each in parametric form.
$L_1 :\left\{ \begin{gathered} x = 6 + 3t \hfill \\ y = 6 + t \hfill \\ z = 2 + 4t \hfill \\ \end{gathered} \right.$ $L_2 :\left\{ \begin{gathered} x = 8 + s \hfill \\ y = 5 + 2s \hfill \\ z = 4 + 2s \hfill \\ \end{gathered} \right.$

Now solve for the parameters.

**foojy** · July 19th 2010, 12:41 PM

The equations were right just the algebra was wrong. I just recalculated them and got it correct. Thanks!

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