Hi Guys,
I have a fundamental doubt on differential of
y = f(x) = ln(ax)
where,
ln - natual logorithm to base e,
a - constant
x - independent variable.
I need to find the value of dy/dx from first principles.
Can anybody help me on this?
Thanks,
Srini
Yes.(I think...)
But there is better way of solving this...
Recall: ln(a*b)=ln(a)+ln(b)
Now:
ln(ax)=ln(a)+ln(x)
so the derivative of ln(ax) is:
{ln(ax)}'= {ln(a)}' + {ln(x)}'
But ln(a) is a constant! ({ln(a)}'=0)
Hence:
{ln(ax)}'= {ln(a)}' + {ln(x)}'= 0 +1/x=1/x